> From: "John Fletcher" <jfl10593@bigpond.net.au>
>
>
> > Dude I told you how to do it...
> >
> > 50% of 127mm = 63.5
> >
> > 31.75/50 = tan(angle) = 0.635
> >
> > Width/1.27 = Distance
> >
> > If subject is 2m wide it must be 78 cm from the camera to occupy 50%
of
> > 5"
>
> If the camera side's half cone of light has tangent = 31.75/50 then
the
> same angle on the subject side should be 1m/distance, then the
distance
> subject to pinhole lens for a subject 2m wide should be 50/31.75
meters or
> 1.5748meters, about twice what you say. Nevertheless, I don't think
that
> answers Colin's question completely. I'll give it a try bellow.
Correct. Its actually twice what I said..
Colin just think of it as simple ratio's and right angled triangles. Try
drawing it out. Whilst lens optics are complex pinhole images can be
thought of as simple line geometry (in this instance).
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Received on Wed Jan 3 22:51:35 2007
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