Dude I told you how to do it...
50% of 127mm = 63.5
31.75/50 = tan(angle) = 0.635
Width/1.27 = Distance
If subject is 2m wide it must be 78 cm from the camera to occupy 50% of
5"
----- Original Message -----
From: "Colin Talcroft" <ctalcroft@yahoo.com>
To: <pinhole-discussion@spitbite.org>
Sent: Thursday, January 04, 2007 1:15 PM
Subject: Re: [pinhole-discussion] Re:Superimposing 2 images taken with 2
FL lenses
> Sorry for the slow response, but thanks for the
> thoughts about superimposing images. I understand the
> way that perspective will alter the images. I don't
> mind that. I'm not looking for a perfect fit, just a
> reasonable correspondence. I'm just looking for a rule
> of thumb. Is it possible to say, for example, that a
> subject occupying 50% of the width of a 4X5 negative
> using a 50mm pinhole at a given distance from the film
> and at X feet will also occupy 50% of the width of the
> negative using a 210mm lens on a 4x5 view camera if
> the film-to-subject distance is some multiple of X, or
> something like that? Seems like it should be a fairly
> simple relationship. I just don't know what it is.
>
> Thanks--and Happy New year to all.
>
> Colin
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Received on Wed Jan 3 20:47:21 2007
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