----- Original Message -----
From: "Wolfgang Thoma" <taco@thoma.be>
> >
> So, let's calculate: focal length 55 devided by f/stop 259 makes a
> pinhole of 0,212 mm devided by 2,56 makes the same as 0,083 inch.
Not that it makes much of a difference!, but the factor to convert mm to
inches is 25.4.
So, 0.212mm divided by 25.4 = 0.0083 inches
> and still have a spare one of 0,087 inch. Not exactly the required size,
> but quite close to it, making it an f/stop of 222.
A 0.087 inches pinhole would give you f/24.9 aperture for a 55mm focal
length ( 55 / [0.087 x 25.4]), may be the pinhole you have is 0.0087
inches, in which case it'd give you an aperture of f/249
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Received on Tue Sep 14 15:13:02 2004
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